Thread: inverse Laplace transform

Hi all,

Using the s shifting theorem to find the inverse Laplace transform of:

F (s) = 3 / (s + 2)^2

I get the right answer but i am not sure if my working out is correct, would be appreciated if someone can tell me.

F(s +2) = L [e^(2t)* f(t)]

L[f(t)] = 3/ s^2

f(t) = L^(-1) [3/ s^2]
= 3t

g(t) = e^(2t) * f(t)
g(t) = 3t*e^(2t)

Thanks in advance,
ArTiCk

Originally Posted by ArTiCK

Hi all,

Using the s shifting theorem to find the inverse Laplace transform of:

F (s) = 3 / (s + 2)^2

I get the right answer but i am not sure if my working out is correct, would be appreciated if someone can tell me.

F(s +2) = L [e^(2t)* f(t)]

L[f(t)] = 3/ s^2

f(t) = L^(-1) [3/ s^2]
= 3t

g(t) = e^(2t) * f(t) Mr F says: This should be . Note that F(s + 2) = F(s - [-2]) ....

g(t) = 3t*e^(2t) Mr F says: This should be

Thanks in advance,
ArTiCk

By the way, * is not a good symbol to use for multiplication when posting laplace transform problems - it could get confused with the convolution operator.