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**latavee** *y = c1 + c2cos x + c3sin x* is the general solution of the differential equation *y''' + y' = 0 *on (-infinity, infinity). Find a member of the family that is a solution with initial conditions *y(pi) = 0,* *y'(pi) = 2, and y''(pi) = -1*.

(1) What is the value of *c1*?

(1) What is the value of *c2*?

(1) What is the value of *c3*?

I can't figure this one out for nothing!

0=c1+c2cos(pi)+c3sin(pi)

0=c1+c2(-1)+c3(0)

0=c1-c2

2=c1+c2(-sin(pi))+c3(cos(pi))

2=c1+c2(0)-c3

-1=c1+c2(cos(pi))+c3(-sin(pi))

-1=c1-c2

How would I solve the three equations to find each? I'm stuck here