
Originally Posted by
latavee
y = c1 + c2cos x + c3sin x is the general solution of the differential equation y''' + y' = 0 on (-infinity, infinity). Find a member of the family that is a solution with initial conditions y(pi) = 0, y'(pi) = 2, and y''(pi) = -1.
(1) What is the value of c1?
(1) What is the value of c2?
(1) What is the value of c3?
I can't figure this one out for nothing!
0=c1+c2cos(pi)+c3sin(pi)
0=c1+c2(-1)+c3(0)
0=c1-c2
2=c1+c2(-sin(pi))+c3(cos(pi))
2=c1+c2(0)-c3
-1=c1+c2(cos(pi))+c3(-sin(pi))
-1=c1-c2
How would I solve the three equations to find each? I'm stuck here