so, my assignment is due in 4 hours, but i can't solve this eqn dy/dt = -y^4 + 2y^3 + 63y^2 my TA told me to isolate the equation for -y^2, and that's what i got: dy/dt = -y^2(y^2 - 2y - 63) = -y^2(y - 9)(y + 7) i have no clue to solve it...
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Originally Posted by boxmailman so, my assignment is due in 4 hours, but i can't solve this eqn dy/dt = -y^4 + 2y^3 + 63y^2 my TA told me to isolate the equation for -y^2, and that's what i got: dy/dt = -y^2(y^2 - 2y - 63) = -y^2(y - 9)(y + 7) i have no clue to solve it... Separate the variables to get Apply the method of partial fractions to integrate the LHS of the equation. Can you take it from here?
thnx a lot, that was really helpful!!!
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