Results 1 to 2 of 2

Math Help - more IVP

  1. #1
    Newbie
    Joined
    Sep 2008
    Posts
    11

    Unhappy more IVP

    y^1 (yprime) + 2y/3 = 1 - x/2 y(0) = yv0 ( y not, or y naught, or however u say it)

    find y naught so that the solution just touches x-axis (can use calc)

    i made it a first order ODE and made the integrating factor (u) = e ^ (int) 2dt/3

    which means that....
    d/dt[y(e2x/3)] = 1- x/2

    so y = 9x - x^2)/(e^2x/3)

    so y naught = 0.184 right?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    Joined
    Jun 2009
    Posts
    660
    Thanks
    133
    No, when you multiply by the integrating factor, the RHS gets multiplied by it as well. You then have an integration by parts (on the RHS) to deal with.
    Also make your mind up as to what variables you are using. Those t's should be x's.
    Follow Math Help Forum on Facebook and Google+

Search Tags


/mathhelpforum @mathhelpforum