make p the subject.

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September 12th 2009, 03:57 AM
Khonics89

make p the subject.

find an explicit formula for P in terms of t....

I'm struggling with this one :(

I know we can do dt/dP = 1/p(2-0.01p)

then apply partial fractions.. and then integerate and then .... thats when its gets abit tricky.

to find C... t=0 when P=50

the answer is 200/1+3e^-?t

I forgot what that something is...

Thanks(Rofl)
September 12th 2009, 04:55 AM
Matt Westwood

Sorry, you've confused me ... what's the equation you're trying to solve?
September 12th 2009, 04:59 AM
e^(i*pi)

Quote:

Originally Posted by Matt Westwood

Sorry, you've confused me ... what's the equation you're trying to solve?

$\frac{dt}{dP} = \frac{1}{p(2-0.01p)}$

(under edit while fixing mistakes)

$dt = \frac{dP}{p(2-0.01p)} = \frac{A}{p} + \frac{B}{2-0.01p}$

$\frac{1}{p(2-0.01p)} = \frac{(2-0.01p)A + Bp}{p(2-0.01p)}$
September 12th 2009, 05:14 PM
Khonics89

Yes, I've done that and went abit further..

then we find the values of a and b which are 1/2 and 1/200 respectively.

then we find C...

then the problem is when I make P the subject ??
September 12th 2009, 05:15 PM
Khonics89

The equation is dt/dp= 1/p(1-0.01P)

to find the constant C use when t=0 P=50 ...

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