Ok, I'm stuck! I've tried everything and can't seem to solve this problem!
dy/dt+2y=1 y(0)=5/2; and find the value of the function t=3seconds
I first tried: dy=1-2y dt
next integrate both sides: u=1-2y u'=-2 dx=-1/2du=t
so after integrating: -1/2ln(1-2y)=t+C
When I plug in the IVP, I'm getting a negative log, So now I'm stuck!