That's a linear DE with constant coefficients and its 'characteristic equation' is...
(1)
But ...
(2)
... so that...
Kind regards
Hi
The section that I am currently busy with is the D operator, I am learning how to find the aux equation and complimentary functions
Its basic maths but unfortunately I am struggling with the higher DE
I need to know what is the simplest way to solve these higher order DE
Please help
In this case it is immediate 'discovering' that makes null the polynomial , so that is a factor of that polynomial. In general we aren't so 'lucky' and in such a case we have to 'attack' a third order algebraic equation, that the Italian mathematicians Scipione del Ferro and Niccolò Fontana first successfully resolved between fifteenth and sixteenth century ...
Kind regards