Results 1 to 2 of 2

Math Help - integration problem

  1. #1
    Junior Member
    Joined
    Mar 2009
    Posts
    41

    integration problem

    The position function x(t) of a particle moving along an x axis is x = 4.00 - 7.00t2, with x in meters and t in seconds. (a) At what time and (b) where does the particle (momentarily) stop? At what (c) negative time and (d) positive time does the particle pass through the origin? Graph x versus t for the range -5 s to +5 s. (e) To shift the curve rightward on the graph, should we include the term +20t (denote 1) or the term -20t (denote 0) in x(t)? (f) Does that inclusion increase (denote 1) or decrease (denote 0) the value of x at which the particle momentarily stops?


    My teacher never got into this subject and i really need help
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member eXist's Avatar
    Joined
    Aug 2009
    Posts
    157
    For part A) Take the derivative and set it equal to 0. f'(x) = v(x) also know as the velocity funciton.
    x = 4.00 - 7.00t^2

    So you get:
    v(x) = -14t
    0 = -14t
    t = 0

    So at time 0, the velocity is 0 (not moving).

    For part B) To find out where, substitute 0 back in as t.
    x = 4 - 7(0)^2
    x = 4

    So at a position of 4, the particle is not moving.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Integration problem
    Posted in the Calculus Forum
    Replies: 2
    Last Post: December 4th 2010, 09:35 PM
  2. Integration Problem
    Posted in the Calculus Forum
    Replies: 6
    Last Post: March 16th 2010, 04:20 PM
  3. Replies: 2
    Last Post: February 19th 2010, 10:55 AM
  4. Integration problem?
    Posted in the Calculus Forum
    Replies: 6
    Last Post: June 3rd 2009, 06:33 PM
  5. Integration problem
    Posted in the Calculus Forum
    Replies: 2
    Last Post: June 2nd 2008, 02:19 AM

Search Tags


/mathhelpforum @mathhelpforum