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Math Help - Vectors Applications 2

  1. #1
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    Vectors Applications 2

    Find x, y, z, if 2(x,-1,4)-3(-4,y,6)-0.5(4,-2,z)=(0,0,0)

    Ok, I think I did this question correct, but the back of the says no.. I am guessing that the back of the book is wrong.. Can someone just verify? Thanks

    2x-2+4=0
    x=-3

    12-3y-18=0
    y=-2

    -2+1-0.5z=0
    z=2

    is this ok?
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  2. #2
    Member eXist's Avatar
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    I got a different linear set of equations:

    <br />
2x + 12 - 2 = 0
    -3y - 2 + 1 = 0
     -.5z + 8 - 18 = 0<br />

    x = -5
    y = -1/3
    z = -20

    Careful how your distributing.
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  3. #3
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    Quote Originally Posted by skeske1234 View Post
    Find x, y, z, if 2(x,-1,4)-3(-4,y,6)-0.5(4,-2,z)=(0,0,0)
    2x-2+4=0
    x=-3

    12-3y-18=0
    y=-2

    -2+1-0.5z=0
    z=2

    is this ok?
    You need to rethink the operations.

    2\left( {x, - 1,4} \right) - 3\left( { - 4,y,6} \right) - 0.5\left( {4, - 2,z} \right) = \left( {2x + 12 - 2, - 2 - 3y + 1,8 - 18 - 0.5z} \right)
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