A pilot plans to travel 300 km east, then 300 km north-east. Show that the resultant bearing is 67.5 degrees.
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Originally Posted by Mr Rayon A pilot plans to travel 300 km east, then 300 km north-east. Show that the resultant bearing is 67.5 degrees. displacement east ... $\displaystyle x = 300+300\cos(45)$ displacement north ... $\displaystyle y = 300\sin(45)$ $\displaystyle \theta = \arctan\left(\frac{y}{x}\right)$
Skeeter has a more mathematical approach, I prefer to drawn the picture. After drawing it, you realize it's an isosceles triangle, and filling in the angles are pretty easy. Take a look at my drawing:
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