one of my HW problems is to find the arc length of the given curve for $\displaystyle x=t^2, y=(3^{1/2}4/3)t^{3/2}, z=3t, 1 <= t <= 4$

now i have the definite integral that goes from 1 to 4, with the equation $\displaystyle (4t^2 + 12t + 9) dt$.

but how do I solve this integral? it seems too hard