How do I exactly differentiate 3^(5x)
Thanxx a lot!
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How do I exactly differentiate 3^(5x)
Thanxx a lot!
Quote:
Originally Posted by xwrathbringerx
The general fromula for f= a^(u(x))
f ' = ln(a) a^(u(x))du/dx
For 3^(5x)
f ' = ln(3)3^(5x)5 = 5ln(3)3^(5x)
http://www.mathhelpforum.com/math-he...04062c89-1.gif
doesn't make sense as x ' = 1
(a^x ) ' = ln(a)*a^x period
for a^(u(x) use the chain rule to obtain
f ' = ln(a) a^(u(x))du/dx
A general method for problems like this is to take the logarithm of both sides. Ifthen
. Now differentiate both sides with respect to x.
The derivative of ln(y) with respect to y isbut since y itself is a function of x, by the chain rule, the derivative of ln(y) with respect to x is
.
so
.