Engineering Centroid Problem

**Cesspit** · August 26th 2009, 07:48 PM

$Centroid = \frac {\int_0^h y\frac {b}{h}(h-y)dy}{\int_0^h \frac {b}{h}(h-y)dy}$

I have the answer which is $\frac {\frac {1}{6}bh^2}{\frac {1}{2}bh}$ which produces $\frac {h}{3}$ as you may know that is a triangle.

However I cant get the same answer, infact I appear to be way off. Can anyone suggest how to integrate this problem? maybe even just the top would be great help.

Thanks to those who can help.

**nirax** · August 26th 2009, 07:53 PM

what is the probelm ?? both the num and denom are polynomials ... u just have to use the formula mindlessly .. where r u stuck ?

**Cesspit** · August 26th 2009, 08:00 PM

on the graph attached the triangles line is $y = \frac {h}{b} (b - x)$ using the standard equation for calculating the y value for the centroid.

**Cesspit** · August 26th 2009, 08:02 PM

I am having trouble integrating the formula in terms of y to get the answers. I cant get the same answer I am getting very different values

**nirax** · August 26th 2009, 09:06 PM

what r u getting ???

**Cesspit** · August 26th 2009, 09:29 PM

The centroid of the triangle, or you might know it as the first moment of area.

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