I have answered these problems already but I am not sure what the correct answers were.
Point P=(3,1/9) lies on 1/x^2
Find slope of secant line PQ for certain values of X:
X=2.5, mSecant=-.097778 <You may want to check the mSecant Val.
X=2.9, mSecant=-.077950 for the values.
X=2.99, mSecant=-.074446
X=2.999, mSecant=-.074111
X=3.5, mSecant=-.058957
X=3.1, mSecant=-.070528
X=3.01, mSecant=-.073705
X=3.001,mSecant=-.074037
b)Estimate the value of the slope of the tagent line at curve P. (use 2.999 and 3.001)
and
Using the slope from B find equation for tagent line to the curve at (3,1/9)
Yes, these all look good.
You have -.074111 and -.074037 for those two values. The best way to use those two numbers is to average them: [tex]\frac{-.074111-.074037}{2}= \frac{.148148}{2}= 0.074074.b)Estimate the value of the slope of the tagent line at curve P. (use 2.999 and 3.001)
so y= 0.074074(x- 3)+ 1/9.and
Using the slope from B find equation for tagent line to the curve at (3,1/9)