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Math Help - Force as a vector 2

  1. #1
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    Force as a vector 2

    A steel wire 40 m long is suspended between two fixed points 20 m apart. A force of 375 pulls the wire down at a point 15 m from one end of the wire. State the tension in each part of the wire.
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  2. #2
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    Quote Originally Posted by skeske1234 View Post
    A steel wire 40 m long is suspended between two fixed points 20 m apart. A force of 375 pulls the wire down at a point 15 m from one end of the wire. State the tension in each part of the wire.
    Try drawing a diagram . I got a right angled triangle with horizontal length 20 , vertical length 15 and hypothenus 25 .

    The force is pulling downwards from the end of the vertical side .

    There will be 2 tensions , T1 and T2 .

    T1 will be 375 N .

    Resolve T2 vertically T2cos53.13 = 375 , T2=625 N

    You can get 53.13 by doing some trigo .

    I am not entirely sure with my answers though .
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  3. #3
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    the answer says:

    375 N, 0 N...........
    and is the 40 m not significant in part of the drawing?
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  4. #4
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    Quote Originally Posted by skeske1234 View Post
    the answer says:

    375 N, 0 N...........
    and is the 40 m not significant in part of the drawing?
    I don see how the tension is 0 N . The wire of 40 m is divided into 2 parts
    25m and 15 m ( where the pulling force is ) .
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  5. #5
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    Quote Originally Posted by mathaddict View Post
    I don see how the tension is 0 N . The wire of 40 m is divided into 2 parts
    25m and 15 m ( where the pulling force is ) .
    Thanks! I was interpreting this as 15 m measured along the 20 m distance, but then I couldn't find the lengths of the sides!

    skeske1234, this gives a triangle with sides of lengths 25, 15, and 20. Since 15^2+ 20^2= 25^2 this triangle satisfies the Pythagorean theorem and, as mathaddict said before, is a right triangle.
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