A steel wire 40 m long is suspended between two fixed points 20 m apart. A force of 375 pulls the wire down at a point 15 m from one end of the wire. State the tension in each part of the wire.
Try drawing a diagram . I got a right angled triangle with horizontal length 20 , vertical length 15 and hypothenus 25 .
The force is pulling downwards from the end of the vertical side .
There will be 2 tensions , T1 and T2 .
T1 will be 375 N .
Resolve T2 vertically T2cos53.13 = 375 , T2=625 N
You can get 53.13 by doing some trigo .
I am not entirely sure with my answers though .
Thanks! I was interpreting this as 15 m measured along the 20 m distance, but then I couldn't find the lengths of the sides!
skeske1234, this gives a triangle with sides of lengths 25, 15, and 20. Since $\displaystyle 15^2+ 20^2= 25^2$ this triangle satisfies the Pythagorean theorem and, as mathaddict said before, is a right triangle.