Originally Posted by
skeske1234 A lawn roller with a mass of 50 kg is being pulled with a force of 320 N. If the handle of the roller makes an angle of 42 degrees with the ground, what horizontal component of the force is causing the roller to move?
So I ended up doing this:
490tan42=x
x=441 N
I got 490 by going 50 kg x 9.8
so I'm not sure if this is right because there are no answers in the back of my book. Please let me know the correct answer to this question and demonstrate the method to get there. thank you