Integrate y=2sin(1/2.546x)+4 between x=0 and x=8
Ok that makes it much easier .
Try u substitution where $\displaystyle u = \frac{1}{2.546}x$
and that makes $\displaystyle du = \frac{1}{2.546}dx$
From there we get:
$\displaystyle y = \int_0^8 \big(2sin\big(u\big)2.546 + 4\big) \, du$
$\displaystyle = \int_0^8 \big(2sin\big(u\big)2.546 \,du + \int_0^8 \big(4\big)\,dx$
$\displaystyle = -5.092cos\big(\frac{1}{2.546}x\big) + 4x$ where x is between 0 and 8
You got the rest ?