# Math Help - Find the intergral of sine function

1. ## Find the intergral of sine function

Integrate y=2sin(1/2.546x)+4 between x=0 and x=8

2. Does the problem look like this:
$y = sin\bigg(\frac{1}{2.546}x\bigg) + 4$
Or this:
$y = sin\bigg(\frac{1}{2.546x}\bigg) + 4$

3. $

y = sin\bigg(\frac{1}{2.546}x\bigg) + 4
$

4. Ok that makes it much easier .

Try u substitution where $u = \frac{1}{2.546}x$
and that makes $du = \frac{1}{2.546}dx$

From there we get:

$y = \int_0^8 \big(2sin\big(u\big)2.546 + 4\big) \, du$

$= \int_0^8 \big(2sin\big(u\big)2.546 \,du + \int_0^8 \big(4\big)\,dx$
$= -5.092cos\big(\frac{1}{2.546}x\big) + 4x$ where x is between 0 and 8

You got the rest ?

5. haha words cannot describe how thankful i am.