y = 15 sin(ωt + a), determine dy/dt.... i'm just confused by the ω on this one
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Originally Posted by Ep!taph y = 15 sin(ωt + a), determine dy/dt.... i'm just confused by the ω on this one It appears that and are arbitrary constants. So you can use the chain rule to find this derivative. Let . Then . So and . Therefore .
ah thanks... just as i thought, what about this one? v = 10(1-e^(-t/5)), determine dv/dt?
Originally Posted by Ep!taph ah thanks... just as i thought, what about this one? v = 10(1-e^(-t/5)), determine dv/dt? What is the problem you are having with this one? (multiply out the bracket, do you still have a problem, what is it? Consider using the chain rule) CB
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