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Math Help - Differentiation

  1. #1
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    Differentiation

    Hi, i'm stuck as to what to do with this problem.

    Find the gradient of y with respect to x

    y=\frac{3\sqrt{\theta^2+1}}{1/2cos(x^2+2\theta)}

    I started by doing this:

    y=\frac{6\sqrt{\theta^2+1}}{cos(x^2+2\theta)}

    But i don't know how to resolve cos(x^2+2\theta)

    Is theta a constant that i just treat as any normal number?

    This would leave the top part as 0 once differentiated. Is this right?

    I can't find anything in my textbooks referring to two unknowns.

    Any help is appreciated.
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  2. #2
    MHF Contributor

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    Quote Originally Posted by andyw View Post
    Hi, i'm stuck as to what to do with this problem.

    Find the gradient of y with respect to x

    y=\frac{3\sqrt{\theta^2+1}}{1/2cos(x^2+2\theta)}

    I started by doing this:

    y=\frac{6\sqrt{\theta^2+1}}{cos(x^2+2\theta)}

    But i don't know how to resolve cos(x^2+2\theta)

    Is theta a constant that i just treat as any normal number?

    This would leave the top part as 0 once differentiated. Is this right?

    I can't find anything in my textbooks referring to two unknowns.

    Any help is appreciated.
    Either \theta is a constant or you are asked to find a "partial derivative" with respect to x which means treating \theta like a constant- so either way, the derivative of the numerator is just 0.
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