I don't know how to do this problem, so if someone could please help me, I'll be grateful: Solve the initial value problem (x2 + 1) squared dy/dx = the square root of(x2 + 1) , y(0) = 1 Thanks
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Originally Posted by turtle I don't know how to do this problem, so if someone could please help me, I'll be grateful: Solve the initial value problem (x2 + 1) squared dy/dx = the square root of(x2 + 1) , y(0) = 1 Thanks
Hello, turtle! Your title was "Trig Substitution" . . . Solve the initial value problem: We have: . Integrate: . Let . . Substitute: . Back-substitute: . . . Since Therefore: .
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