I don't know how to do this problem, so if someone could please help me, I'll be grateful:

Solve the initial value problem

(x2 + 1) squared dy/dx = the square root of(x2 + 1) , y(0) = 1

Thanks

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- Jan 11th 2007, 04:52 PMturtleTrig Substitution
I don't know how to do this problem, so if someone could please help me, I'll be grateful:

Solve the initial value problem

(x2 + 1) squared dy/dx = the square root of(x2 + 1) , y(0) = 1

Thanks - Jan 11th 2007, 05:27 PMThePerfectHacker
- Jan 11th 2007, 08:44 PMSoroban
Hello, turtle!

Your title was "Trig Substitution" . . .

Quote:

Solve the initial value problem:

We have: .

Integrate: .

Let

. .

Substitute: .

Back-substitute: .

. .

Since

Therefore: .