i have a question. is a function limit x tending to 1 f(x)= (x^2-1)/(x-1) is contineous at every point or it is discontineous at x=1? also the simplified form of above function i.e (x+1) has the same contineuity as the above function??
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Originally Posted by pravinjaggu i have a question. is a function limit x tending to 1 f(x)= (x^2-1)/(x-1) is contineous at every point or it is discontineous at x=1? also the simplified form of above function i.e (x+1) has the same contineuity as the above function?? . However, is discontinuous at . There is a hole in the function at that value since is a term common to the numerator and denominator of the function.
Originally Posted by pravinjaggu i have a question. is a function limit x tending to 1 f(x)= (x^2-1)/(x-1) is contineous at every point or it is discontineous at x=1? also the simplified form of above function i.e (x+1) has the same contineuity as the above function?? is discontinuos at because it is not DEFINED there. This is a REMOVABLE discontinuity because
Originally Posted by VonNemo19 is discontinuos at because it is not DEFINED there. This is a REMOVABLE discontinuity because Hello there is the graphe
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