lim 1/x + 3 = 3 right? x -> ∞ what about lim x -> ∞ 3x + 2/4x? and lim 5x - 8/7x^2 - 14? x -> ∞
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For limits at infinity consider the ratio of the highest powered terms lim(3x+2)/(4x) = lim 3x/4x = 3/4 lim(5x-8)/(7x^2-14) = lim 5x/7x^2 = lim 5/(7x) = 0
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