Originally Posted by

**skeske1234** Given f(x)=(x^2-x-2)/(x^2+x), find the vertical and horizontal asymptotes and sketch the graph near the asymptotes.

VA

x=0 or x=-1

HA

as x -> +-infinity, y->1

So that is my work above and I graphed this all too. But.... my question comes here.

When I graph the function f(x) using software, there appears to be no vertical asmptote of x=-1, only x=0 is a VA... This is really strange because I do believe there are two asymptotes..

to find asymptote, set denominator =0 and solve for x.

x^2 + x = 0

x(x+1)=0

x=0 or x=-1

so?? what did I do wrong now?

Note: I did not type the eqtn of the function wrong into graphing software.