Hi, I need to integrate cos^3(x).
So far I have:∫cos^3(x) = ∫cos(x)(1-sin^2(x)) = ∫cos(x) -∫cos(x)sin^2(x)= sin(x) - (1/3) sin^3(x) = 1/3 (3sin(x) - sin^3(x))
How do I get from this to: 1/12 (9sin(x) + sin(3x))
Is there a special trig identity?
Hi, I need to integrate cos^3(x).
So far I have:∫cos^3(x) = ∫cos(x)(1-sin^2(x)) = ∫cos(x) -∫cos(x)sin^2(x)= sin(x) - (1/3) sin^3(x) = 1/3 (3sin(x) - sin^3(x))
How do I get from this to: 1/12 (9sin(x) + sin(3x))
Is there a special trig identity?