Problem: Find the slope of a straight line that passes through the point (-2, 0) and is tangent to the curve y = sq.root of x.

Okay, so I start by finding the derivative of y which is 1/(2*sq.root of x).

This line is tangent to the curve y = sq.root of x. However, I am uncertain as to how I should proceed in making sure this function passes through (-2, 0). Any help would be greatly appreciated!