Rectangle ABCD has A and D on the equal sides of an isoceles triangle and B and C on its base. If AB=2 cm and BC=6 cm, find the value of the base angle that produces the triangle of minimum area.

So I first found the length of one side of the isosceles triangle by using SOHCAHTOA

looks like this

sinx=o/h

sinx=2/h

h=2/sinx

Now I will min the area of the triangle

SAS formula:

A=0.5 (side 1 x side 2) sinx

A=(6/sinx) (sinx)

This is where I am having trouble, the sinx cancels out and that isnt good because now the derivative....?

Can someone let me know where I went wrong so far and guide me in the right direction. Let me know. the answer is 0.58800 btw