Rectangle ABCD has A and D on the equal sides of an isoceles triangle and B and C on its base. If AB=2 cm and BC=6 cm, find the value of the base angle that produces the triangle of minimum area.
So I first found the length of one side of the isosceles triangle by using SOHCAHTOA
looks like this
Now I will min the area of the triangle
A=0.5 (side 1 x side 2) sinx
This is where I am having trouble, the sinx cancels out and that isnt good because now the derivative....?
Can someone let me know where I went wrong so far and guide me in the right direction. Let me know. the answer is 0.58800 btw