Finding the x-intercepts of a quartic

**linearalgebra** · August 18th 2009, 12:40 PM

Hi!
I have to sketch the graph of the following function, but I dont remember how I'm supposed to find the x-intercepts of a quartic. I know I have to set y=0 but Im having difficulty factoring.

The function is f(x) =x^4 - 4x^3

Can someone please gice me an explanation as to how I should go about solving this?

**red_dog** · August 18th 2009, 02:05 PM

$f(x)=0\Rightarrow x^4-4x^3=0\Rightarrow x^3(x-4)=0\Rightarrow x=0, \ x=4$

**linearalgebra** · August 18th 2009, 02:20 PM

I just worked that out as well!
Thanks so much!!

**linearalgebra** · August 18th 2009, 02:22 PM

This function has no asymptotes right?
Because its a polynomial, meaning there are no restrictions?

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