Determine whether the series converges or diverges (sin^2 n) / (n^2 + 4) The summation goes from n=1 to n=infinity
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Hi $\displaystyle 0 \leq \frac{\sin^2 n}{n^2 + 4} \leq \frac{1}{n^2 + 4} \leq \frac{1}{n^2}$
Originally Posted by running-gag Hi $\displaystyle 0 \leq \frac{\sin^2 n}{n^2 + 4} \leq \frac{1}{n^2 + 4} \leq \frac{1}{n^2}$ It is therefor convergent by the P-series Test correct? because we showed that it is <= to 1/n^2 and since the p is greater than 1 it will converge?
Yes.
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