Guys, how do I differentiate (a) x/7 and (b) (1/4)(√x) And finally, what is Answer of (a) / Answer of (b) Thank You!
Last edited by mr fantastic; August 18th 2009 at 07:43 AM. Reason: Changed post title
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as we know d(x^n)/dx nx^(n-1) and d(ax)/dx = a d(x)/dx where a is a constant therefor d(x/7)/dx = (1/7) d(x)/dx=1/7 (as d(x)/dx=1) you may try other one yourself.feel free to ask if you face any problem.
Originally Posted by nikhil as we know d(x^n)/dx nx^(n-1) and d(ax)/dx = a d(x)/dx where a is a constant therefor d(x/7)/dx = (1/7) d(x)/dx=1/7 (as d(x)/dx=1) you may try other one yourself.feel free to ask if you face any problem. Am I right in saying that a) dy/dx = 1/7 and b) dy/dx = 1 / 8√x so my rate of substitution would be (1/7) / (1 / (8√x))/ Is there a way to simplify this further?
Originally Posted by Archimedes Am I right in saying that a) dy/dx = 1/7 Mr F says: Correct. and b) dy/dx = 1 / 8√x Mr F says: If you mean dy/dx = 1 /(8√x), then yes you're answer is correct. so my rate of substitution would be (1/7) / (1 / (8√x))/ Is there a way to simplify this further? Mr F says: Yes. Note that (a/b) / (c/d) = (ad)/(bc) ... ..
well you got the differentiation correct now simply (1/7)/(1/8(x)^(1/2))=(8(x)^(1/2))/7
Ok now Ive got (1 / (8√x)) / 7 Does that mean my final answer is (8√x)/7 ? Edit: Nikhal confirmed in above post. Thanks to both of you guys so much!
yes that's the final answer.
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