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Math Help - Tangent to a curve that passes through a given point

  1. #1
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    Tangent to a curve that passes through a given point

    y = -3.39x2 + 3.21x Determine the positions on the curve (x,y), of all tangents that pass through the point (-4.87,67.22). Enter none if no tangent exists. ENTER THE LEFT-MOST TANGENT POINT (the one with the lowest x-value) IN THE FIRST BOX!
    Round all values to FOUR decimal places, using the normal convention. Pad with zeros if necessary.
    Example1: (-0.2305,2.3670)

    Left-most tangent point (x,y) = [correct answer is (-11.8095,-510.6958)]
    Right-most tangent point (x,y) = [correct answer is (2.0695,-7.8761)]

    I've tried the approach you've listed here (http://www.mathhelpforum.com/math-he...tml#post351621) and it just doesn't seem to work for me. I was wondering if you could post a step by step approach so i can understand the process a little bit better.

    Thank you

    Billy
    Last edited by mr fantastic; August 18th 2009 at 06:54 AM. Reason: Moved the post, added the link.
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  2. #2
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    Quote Originally Posted by jebusdood View Post
    y = -3.39x2 + 3.21x Determine the positions on the curve (x,y), of all tangents that pass through the point (-4.87,67.22). Enter none if no tangent exists. ENTER THE LEFT-MOST TANGENT POINT (the one with the lowest x-value) IN THE FIRST BOX!
    Round all values to FOUR decimal places, using the normal convention. Pad with zeros if necessary.
    Example1: (-0.2305,2.3670)

    Left-most tangent point (x,y) = [correct answer is (-11.8095,-510.6958)]
    Right-most tangent point (x,y) = [correct answer is (2.0695,-7.8761)]

    I've tried the approach you've listed here and it just doesn't seem to work for me. I was wondering if you could post a step by step approach so i can understand the process a little bit better.

    Thank you

    Billy
    Hey Billy,

    You are obviously in my Calc course at USC atm!!

    I am still having drama's with this question too

    I drew a picture, and sort other idea's but still no luck.

    Miss B
    Last edited by missb; August 18th 2009 at 03:49 AM.
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  3. #3
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    Quote Originally Posted by jebusdood View Post
    y = -3.39x2 + 3.21x Determine the positions on the curve (x,y), of all tangents that pass through the point (-4.87,67.22). Enter none if no tangent exists. ENTER THE LEFT-MOST TANGENT POINT (the one with the lowest x-value) IN THE FIRST BOX!
    Round all values to FOUR decimal places, using the normal convention. Pad with zeros if necessary.
    Example1: (-0.2305,2.3670)
    Left-most tangent point (x,y) = [correct answer is (-11.8095,-510.6958)]
    Right-most tangent point (x,y) = [correct answer is (2.0695,-7.8761)]

    I've tried the approach you've listed here (http://www.mathhelpforum.com/math-he...tml#post351621) and it just doesn't seem to work for me. I was wondering if you could post a step by step approach so i can understand the process a little bit better.

    Thank you

    Billy
    Please show what you've done and where you get stuck. A way of solving this sort of question is given in the link.
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