1. doubling time

The population of the world is doubling every 35 a. In 1987 the total population reached 5 billion. find the projected world population for the year 2001.
USE THE EXPONENTIAL GROWTH FORMULA.
y=y_o(e)^(kt)
35a=5e^(1987t)
ln7a/1987=k

y=5e^[(ln7a/1987)(2001)]
=35.6
this is wrong, the answer is 6.6 billion

2. Originally Posted by skeske1234
The population of the world is doubling every 35 a. In 1987 the total population reached 5 billion. find the projected world population for the year 2001.
USE THE EXPONENTIAL GROWTH FORMULA.
y=y_o(e)^(kt)
35a=5e^(1987t)
ln7a/1987=k
doubling every 35 years?

let 1987 be t = 0

$\displaystyle y = 5e^{kt}$

$\displaystyle 10 = 5e^{35k}$

solve for k, then use the original equation to evaluate y when t = 14 (2001)

3. Originally Posted by skeeter
doubling every 35 years?

let 1987 be t = 0

$\displaystyle y = 5e^{kt}$

$\displaystyle 10 = 5e^{35k}$

solve for k, then use the original equation to evaluate y when t = 14 (2001)
no, doubling every 35 a.

There is an a there.. and no that is not a typo because there are other questions in the textbook that read a following a number too.. I am not too sure about this eg.

Uranium-28 has a half life of 4.5x10^9 a.
Find the mass that remains from this sample afer 1000 a. Find the rate of decrease of the mass after 10000 a.

So there is an a? :S

4. fine ... every $\displaystyle 35a$

let 1987 be t = 0

$\displaystyle y = 5e^{kt}$

$\displaystyle 10 = 5e^{(35a)k}$

solve for $\displaystyle k$ in terms of $\displaystyle a$, then use the original equation to evaluate y when t = 14 (2001)