To find the slope, first find , then subs. t = 3
Note: slope = first derivative
[SIZE=+1]The equation of the tangent line to the curve
r(t) = t^2 i + 3t j + t3 k at the point where t = 3
i found the point 9,9,27 by subbing in t=3 into the r(t) position equation, however im unsure how they find the (TANGENT) slope s*(6,3,27).
so im left with this at the moment (9,9,27)+s(?,?,?)