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Math Help - Equation of tangent line in 3d

  1. #1
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    Equation of tangent line in 3d

    [SIZE=+1]The equation of the tangent line to the curve
    r(t) = t^2 i + 3t j + t3 k at the point where t = 3



    i found the point 9,9,27 by subbing in t=3 into the r(t) position equation, however im unsure how they find the (TANGENT) slope s*(6,3,27).

    so im left with this at the moment (9,9,27)+s(?,?,?)
    Last edited by sebko; August 16th 2009 at 05:09 AM.
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  2. #2
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    Hi sebko

    To find the slope, first find \frac{d}{dt}r(t), then subs. t = 3

    Note: slope = first derivative
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  3. #3
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    Sorry i meant, the tangent slope. "s" is the parameter,
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  4. #4
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    sorry was getting confused with tangent and normal...... how would you find the normal curve?
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  5. #5
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    Hi sebko

    Yes, the tangent slope = first derivative

    \text{slope for normal}=\frac{-1}{\text{tangent slope}}
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