[SIZE=+1]The equation of the tangent line to the curve

r(t) = t^2i+ 3tj+ t3kat the point where t = 3

i found the point 9,9,27 by subbing in t=3 into the r(t) position equation, however im unsure how they find the (TANGENT) slope s*(6,3,27).

so im left with this at the moment (9,9,27)+s(?,?,?)