1. If f(x)=log_2[log_3(x)], find f'(4)
can someone check to see if my answers match yours?
f'(x)=1/[(xln3)]/[log_3(x)ln2]
=1/[xln3ln2log_3(x)]
f'(4)=1/[4ln3ln2log_3(4)]
2. Find the equation of the tangent to the curve defined by y=lnx-1 that is parallel to the straight line with equation 3x-6y-1=0.
M=0.5
y=lnx-1
y'=1/x
M_t=0.5
0.5=1/x
x=2
at x=2
y=lnx-1
y=ln2-1
y=mx+b
ln2-1=0.5(2)+b
ln2-1=b
therefore my answer is:
y=0.5x+ln2-1
Thanks in advance