1. If f(x)=log_2[log_3(x)], find f'(4)

can someone check to see if my answers match yours?

f'(x)=1/[(xln3)]/[log_3(x)ln2]

=1/[xln3ln2log_3(x)]

f'(4)=1/[4ln3ln2log_3(4)]

2. Find the equation of the tangent to the curve defined by y=lnx-1 that is parallel to the straight line with equation 3x-6y-1=0.

M=0.5

y=lnx-1

y'=1/x

M_t=0.5

0.5=1/x

x=2

at x=2

y=lnx-1

y=ln2-1

y=mx+b

ln2-1=0.5(2)+b

ln2-1=b

therefore my answer is:

y=0.5x+ln2-1

Thanks in advance