Find an equation for the tangent line to the curve y=(e^x)/(1+lnx) at the point where x=1.
Can someone check my work please?
y=e^x/(1+lnx)
y'=[e^x(1+lnx)-e^x(1/x)]/(1+lnx)^2
f'(1)=e(0)/1
=0
y=mx+b
e=0(1)+b
e=b
therefore the equation of the tangent is
y=e
Is this correct? thank you in advance!