multiply both sides by sqrt(x)
then sqrt(xy) < (y-x)/2 + x
result follows
a. Use the Mean Value Theorem to show that for 0<x<y,
√y - √x < (y-x)/2√x.
b. Use part (a), above, to conclude that for 0<x<y,
√xy < (y+x)/2
I solved part (a), but I don't know how to solve part (b). Can somebody help please? Thanks!!