Find the equation of the tangent to the curve defined by that is parallel to the line represented by 3x-y-9=0

This is my work, can someone check it please? I'm not sure if i have the rules of the natural exponential function correct.

First off I want to say, I know that

BUT

is there anything for

Now I will continue.

y'=3 at x=?

x=-lne/ln2

x=-1/ln2

y=mx+b

y=mx+b

3(-1/ln2)+b=

b=

Final answer:

y=3x+