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Math Help - how to break it into dx and dy

  1. #1
    MHF Contributor
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    how to break it into dx and dy

    x is from 0 to 1
    y is from 3 to 3

    <br />
\int_{0}^{3}\int_{0}^{1}(2x+10y+4)dxdy=\int_{0}^{3  }\int_{0}^{1}(2xdxdy+10ydxdy+4dxdy)=<br />
    <br />
=\int_{0}^{3}2xdx\int_{0}^{1}(+10y+4)dy<br />
    correct?
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  2. #2
    MHF Contributor Amer's Avatar
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    Quote Originally Posted by transgalactic View Post
    x is from 0 to 1
    y is from 3 to 3

    <br />
\int_{0}^{3}\int_{0}^{1}(2x+10y+4)dxdy=\int_{0}^{3  }\int_{0}^{1}(2xdxdy+10ydxdy+4dxdy)=<br />
    <br />
=\int_{0}^{3}2xdx\int_{0}^{1}(+10y+4)dy<br />
    correct?
    you can't break integral that's not correct

    \int_{0}^{3}\int_{0}^{1} (2x+10y+4)dxdy integrate with respect to x first

    \int_{0}^{3} \frac{2x^2}{2} + 10yx +4x \mid_{0}^{1}

    \int_{0}^{3} 1+10y+4 dy integrate with respect to y
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  3. #3
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    thanks i understan now
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