I'm having trouble with this question on mean value theorem
1. x+(96/x) on interval [6,16]
the problem with this equation is i get 0/(10) and when i check the answer is 4sq.rt(6) I'm using the f(b)-f(a)/b-a so what am i'm missing?
The MVT says that there will be at least one place in an interval [a,b] where the slope of the tangent line to the graph will have the same slope as the secant line through [a,f(a)] and [b,f(b)]. You have found the slope of the secant line. So, you're not done.
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