I'm having trouble with this question on mean value theorem

1. x+(96/x) on interval [6,16]

the problem with this equation is i get 0/(10) and when i check the answer is 4sq.rt(6) I'm using the f(b)-f(a)/b-a so what am i'm missing?

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- Aug 13th 2009, 06:21 PMgoldenrollMean Value Theorem
I'm having trouble with this question on mean value theorem

1. x+(96/x) on interval [6,16]

the problem with this equation is i get 0/(10) and when i check the answer is 4sq.rt(6) I'm using the f(b)-f(a)/b-a so what am i'm missing? - Aug 13th 2009, 07:31 PMVonNemo19
- Aug 13th 2009, 07:37 PMgoldenroll
that comes out to (22-22)/10? because the answer in the book says it come out to 4sq.rt6,

- Aug 13th 2009, 07:41 PMVonNemo19
- Aug 13th 2009, 07:45 PMgoldenroll
hahaha, I guess we just found out were I got lost at. when you say I have only done the right side of the equation what do you mean.

- Aug 13th 2009, 07:54 PMVonNemo19
Equations have right sides, and then they have left sides. Soooooo,

*generally*when we "solve" equations, we isolate the variable. In this case, the variable would be x. So, your task is to move everything to one side of the equation**except**x.

The MVT says that there will be at least one place in an interval [a,b] where the slope of the tangent line to the graph will have the same slope as the secant line through [a,f(a)] and [b,f(b)]. You have found the slope of the secant line. So, you're not done.

(Party)(Party)Start pressing the (Yes) button!(Party)(Party) - Aug 13th 2009, 08:04 PMgoldenroll
oh, lamo, well I finally got the right answer when I finished the other side lol. Oh and just realized where the thanks button was lol.

- Aug 13th 2009, 08:09 PMVonNemo19