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Math Help - Find the area of the region bounded by the curves...

  1. #1
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    Find the area of the region bounded by the curves...

    Find the area of the region bounded by the curves y = sin (π x/2), y = x-2x.

    I'm stuck with the point of intersection: sin (π x/2) = x-2x.



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  2. #2
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    Quote Originally Posted by sun1 View Post
    Find the area of the region bounded by the curves y = sin (π x/2), y = x-2x.

    I'm stuck with the point of intersection: sin (π x/2) = x-2x.



    x=0, 2.
    Last edited by mr fantastic; September 19th 2009 at 01:04 AM. Reason: Restored original reply
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  3. #3
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    Quote Originally Posted by luobo View Post
    x=0, 2.
    Thanks, but how did you get to this solution?
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  4. #4
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    luobo did not solve \sin(\frac{\pi}{2}x) = x^2-2x

    The fact that both these functions have common zeros at 0 and 2 was used.

    You should consider the fact that \sin(\frac{\pi}{2}x) has period of 4 to help you understand
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  5. #5
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    Quote Originally Posted by pickslides View Post
    luobo did not solve \sin(\frac{\pi}{2}x) = x^2-2x

    The fact that both these functions have common zeros at 0 and 2 was used.

    You should consider the fact that \sin(\frac{\pi}{2}x) has period of 4 to help you understand
    Right.
    Last edited by mr fantastic; September 19th 2009 at 01:05 AM. Reason: Restored original reply
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