Find the area of the region bounded by the curves y = sin (π x/2), y = x²-2x.

I'm stuck with the point of intersection: sin (π x/2) = x²-2x.

Printable View

- August 13th 2009, 04:44 PMsun1Find the area of the region bounded by the curves...
Find the area of the region bounded by the curves y = sin (π x/2), y = x²-2x.

I'm stuck with the point of intersection: sin (π x/2) = x²-2x.

- August 13th 2009, 04:52 PMluobo
- August 13th 2009, 04:58 PMsun1
- August 13th 2009, 05:17 PMpickslides
luobo did not solve

The fact that both these functions have common zeros at 0 and 2 was used.

You should consider the fact that has period of 4 to help you understand - August 13th 2009, 05:27 PMluobo