Hi, this is probably dead easy for most of you but can you help me re-arrange this formula so that CºC¹ are the subject.
The formula is:
F= 1/(2π√(Rº R¹ Cº C¹))
F equals the inverse of two pi times the square root of Rº x R¹ x Cº x C¹
Thanks
Hi, this is probably dead easy for most of you but can you help me re-arrange this formula so that CºC¹ are the subject.
The formula is:
F= 1/(2π√(Rº R¹ Cº C¹))
F equals the inverse of two pi times the square root of Rº x R¹ x Cº x C¹
Thanks
Hi J4553
I think it's better if you try it by yourself. Matt Westwood's advice is excellent !
$\displaystyle F=\frac{1}{2\pi\sqrt{R_0 R_1 C_0 C_1}}$
Steps (as suggested by Matt Westwood) :
1. Square both sides
2. Multiply both sides by $\displaystyle C_0 C_1$
3. Divide both sides by $\displaystyle F^2$
Hi J4553
Your answer is wrong ^^
$\displaystyle F=\frac{1}{2\pi\sqrt{R_0 R_1 C_0 C_1}}$
If you square both sides, you'll get :
$\displaystyle F^2=\frac{1}{4\pi^2{R_0 R_1 C_0 C_1}}$
Then, multiply both sides by $\displaystyle C_0 C_1$ will give you :
$\displaystyle F^2C_0 C_1=\frac{1}{4\pi^2{R_0 R_1}}$
Finally, Divide both sides by $\displaystyle F^2$ will give you....^^