1. ## Rearrange Formula

Hi, this is probably dead easy for most of you but can you help me re-arrange this formula so that CºC¹ are the subject.

The formula is:
F= 1/(2π√(Rº R¹ Cº C¹))
F equals the inverse of two pi times the square root of Rº x R¹ x Cº x C¹
Thanks

2. Square it, multiply by $\displaystyle C_0 C_1$ and then divide by $\displaystyle F^2$.

3. Thanks but my maths sucks.
So if someone could just tell me what equals, that'd be great.
This is for an extensive project building a graphic equalizer and I'd really not waste time stuck on something like this

4. Hi J4553

I think it's better if you try it by yourself. Matt Westwood's advice is excellent !

$\displaystyle F=\frac{1}{2\pi\sqrt{R_0 R_1 C_0 C_1}}$

Steps (as suggested by Matt Westwood) :
1. Square both sides

2. Multiply both sides by $\displaystyle C_0 C_1$

3. Divide both sides by $\displaystyle F^2$

5. Steps (as suggested by Matt Westwood) :
1. Square both sides

2. Multiply both sides by

3. Divide both sides by

Ok I got =/(2 π x Rº x R¹)

Yes / No / Way Off?

6. Hi J4553

$\displaystyle F=\frac{1}{2\pi\sqrt{R_0 R_1 C_0 C_1}}$

If you square both sides, you'll get :

$\displaystyle F^2=\frac{1}{4\pi^2{R_0 R_1 C_0 C_1}}$

Then, multiply both sides by $\displaystyle C_0 C_1$ will give you :

$\displaystyle F^2C_0 C_1=\frac{1}{4\pi^2{R_0 R_1}}$

Finally, Divide both sides by $\displaystyle F^2$ will give you....^^

7. Second attempt...

=/(4 π ² x Rº x R¹)

8. Hi J4553

Still wrong ^^

$\displaystyle F^2C_0 C_1=\frac{1}{4\pi^2{R_0 R_1}}$

Divide both sides by F^2 will give you :

$\displaystyle C_0 C_1 = \frac{1}{4\pi^2{R_0 R_1}F^2}$

9. Well I tried, thanks for your help!

10. Originally Posted by J4553
Well I tried, thanks for your help!
Yes you've tried. And that makes you worthy being helped