Hi, this is probably dead easy for most of you but can you help me re-arrange this formula so that CºC¹ are the subject.

The formula is:

F= 1/(2π√(Rº R¹ Cº C¹))

F equals the inverse of two pi times the square root of Rº x R¹ x Cº x C¹

Thanks

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- August 10th 2009, 10:06 PMJ4553Rearrange Formula
Hi, this is probably dead easy for most of you but can you help me re-arrange this formula so that CºC¹ are the subject.

The formula is:

F= 1/(2π√(Rº R¹ Cº C¹))

F equals the inverse of two pi times the square root of Rº x R¹ x Cº x C¹

Thanks - August 10th 2009, 10:58 PMMatt Westwood
Square it, multiply by and then divide by .

- August 10th 2009, 11:33 PMJ4553
Thanks but my maths sucks.

So if someone could just tell me what http://www.mathhelpforum.com/math-he...0dfe0e89-1.gif equals, that'd be great.

This is for an extensive project building a graphic equalizer and I'd really not waste time stuck on something like this (Happy) - August 11th 2009, 02:25 AMsongoku
Hi J4553

I think it's better if you try it by yourself. Matt Westwood's advice is excellent !

Steps (as suggested by Matt Westwood) :

1. Square both sides

2. Multiply both sides by

3. Divide both sides by - August 11th 2009, 04:59 AMJ4553
http://www.mathhelpforum.com/math-he...79ea93a6-1.gif

Steps (as suggested by Matt Westwood) :

1. Square both sides

2. Multiply both sides by http://www.mathhelpforum.com/math-he...0dfe0e89-1.gif

3. Divide both sides by http://www.mathhelpforum.com/math-he...8ee19dbf-1.gif

Ok I got http://www.mathhelpforum.com/math-he...0dfe0e89-1.gif=http://www.mathhelpforum.com/math-he...8ee19dbf-1.gif/(2 π x Rº x R¹)

Yes / No / Way Off?

- August 11th 2009, 05:13 AMsongoku
Hi J4553

Your answer is wrong ^^

If you square both sides, you'll get :

Then, multiply both sides by will give you :

Finally, Divide both sides by will give you....^^ - August 11th 2009, 05:19 AMJ4553
Second attempt...

http://www.mathhelpforum.com/math-he...0dfe0e89-1.gif=http://www.mathhelpforum.com/math-he...8ee19dbf-1.gif/(4 π ² x Rº x R¹)

- August 11th 2009, 05:23 AMsongoku
Hi J4553

Still wrong ^^

Divide both sides by F^2 will give you :

:) - August 11th 2009, 05:25 AMJ4553
Well I tried, thanks for your help! (Rock)

- August 11th 2009, 05:27 AMsongoku