# Rearrange Formula

• August 10th 2009, 10:06 PM
J4553
Rearrange Formula
Hi, this is probably dead easy for most of you but can you help me re-arrange this formula so that CºC¹ are the subject.

The formula is:
F= 1/(2π√(Rº R¹ Cº C¹))
F equals the inverse of two pi times the square root of Rº x R¹ x Cº x C¹
Thanks
• August 10th 2009, 10:58 PM
Matt Westwood
Square it, multiply by $C_0 C_1$ and then divide by $F^2$.
• August 10th 2009, 11:33 PM
J4553
Thanks but my maths sucks.
So if someone could just tell me what http://www.mathhelpforum.com/math-he...0dfe0e89-1.gif equals, that'd be great.
This is for an extensive project building a graphic equalizer and I'd really not waste time stuck on something like this (Happy)
• August 11th 2009, 02:25 AM
songoku
Hi J4553

I think it's better if you try it by yourself. Matt Westwood's advice is excellent !

$F=\frac{1}{2\pi\sqrt{R_0 R_1 C_0 C_1}}$

Steps (as suggested by Matt Westwood) :
1. Square both sides

2. Multiply both sides by $C_0 C_1$

3. Divide both sides by $F^2$
• August 11th 2009, 04:59 AM
J4553
• August 11th 2009, 05:13 AM
songoku
Hi J4553

$F=\frac{1}{2\pi\sqrt{R_0 R_1 C_0 C_1}}$

If you square both sides, you'll get :

$F^2=\frac{1}{4\pi^2{R_0 R_1 C_0 C_1}}$

Then, multiply both sides by $C_0 C_1$ will give you :

$F^2C_0 C_1=\frac{1}{4\pi^2{R_0 R_1}}$

Finally, Divide both sides by $F^2$ will give you....^^
• August 11th 2009, 05:19 AM
J4553
• August 11th 2009, 05:23 AM
songoku
Hi J4553

Still wrong ^^

$F^2C_0 C_1=\frac{1}{4\pi^2{R_0 R_1}}$

Divide both sides by F^2 will give you :

$C_0 C_1 = \frac{1}{4\pi^2{R_0 R_1}F^2}$

:)
• August 11th 2009, 05:25 AM
J4553
Well I tried, thanks for your help! (Rock)
• August 11th 2009, 05:27 AM
songoku
Quote:

Originally Posted by J4553
Well I tried, thanks for your help! (Rock)

Yes you've tried. And that makes you worthy being helped (Happy)