Calculate, using direct integration, the value of e^2t given that s > -2. and... e^t = 1/s-1 for s > 1 Any help on how to do this direct integration would be great guys, thank you
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s,t? Are you asking about LaPlace transforms?
yes. sorry, i didnt put the laplace sign at the front
Originally Posted by tone999 Calculate, using direct integration, the value of e^2t given that s > -2. and... e^t = 1/s-1 for s > 1 Any help on how to do this direct integration would be great guys, thank you By definition: . Therefore: . It's expected you can calculate an improper integral like this one.
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