Calculate, using direct integration, the value of e^2t

given that s > -2.

and...

e^t = 1/s-1

for s > 1

Any help on how to do this direct integration would be great guys, thank you

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- Aug 10th 2009, 03:56 PMtone999Direct Integration
Calculate, using direct integration, the value of e^2t

given that s > -2.

and...

e^t = 1/s-1

for s > 1

Any help on how to do this direct integration would be great guys, thank you - Aug 11th 2009, 12:51 AMmatheagle
s,t? Are you asking about LaPlace transforms?

- Aug 11th 2009, 04:26 AMtone999
yes. sorry, i didnt put the laplace sign at the front

- Aug 11th 2009, 04:36 AMmr fantastic