$\displaystyle y={(7x-2)^{0.5}/(5x+3)}^{0.5}$

can someone check my work? thanks

$\displaystyle y'=0.5{(7x-2)/(5x+3)}^{-0.5}{(7)(5x+3)-(7x-2)(5)}/{(5x+3)^2}$

$\displaystyle y'=0.5{(7x-2)/(5x+3)}^{-0.5}{(31)/{(5x+3)^2}}$

$\displaystyle y'=(31)/{2(5x+3)^{1.5}(7x-2)^{0.5}}$