Can anyone please tell me where to go with this problem.

A chain hangs in a shape called a catenary, the equatio of which is;

f(x) = a*cosh(x/a)

Determine value ox when f(x)=48 and a=35.

Thanks in advance.

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- Aug 9th 2009, 11:50 AMady72Determine value of x
Can anyone please tell me where to go with this problem.

A chain hangs in a shape called a catenary, the equatio of which is;

f(x) = a*cosh(x/a)

Determine value ox when f(x)=48 and a=35.

Thanks in advance. - Aug 9th 2009, 11:55 AMRandom Variable
- Aug 9th 2009, 12:09 PMady72
I'm still none the wiser, I need to know how to get x on it's own.

I'm struggling with this one. - Aug 9th 2009, 12:14 PMRandom Variable

- Aug 9th 2009, 12:17 PMady72
Hi, I have tried that but when I place the value of x back into original formula it doesn't come back to f(x)=48.

- Aug 9th 2009, 12:26 PMRandom Variable
- Aug 9th 2009, 12:27 PMady72
Sorry, I,ve got it now.

I wasn't putting it to calculator correctly.

Thanks for your advice!!