Ok, I'm bad at space geometry and this is a tricky one.
I almost forgot the diagram, it's in the reply.
Find an equation of the plane with x-intercept a, y-intercept b, and z-intercept c.
To find the equation of a plane I need a normal vector and a point. I have the points: which can give me some vectors. I attached a picture so you can see my reasoning, however it isn't suppose to represent this particular plane. In general:
(1) where r may be either vector or and is the vector with terminal point (Note that this notation corresponds to the diagram.)
If I arbitrarily take as the terminal point of , I have . The vector along is , along , we have . Using equation (1) I have:
I find the normal vector using the determinant. I obtain:
If I plug in any point into (3), I don't get the correct answer which is:
Where am I going wrong here?