The distance-time relationship for a moving object is given by s(t)=kt^2+(6k^2-10k)t+2k, where k is a non-zero constant.
a) show that the acceleration is constant
b) find the time at which the velocity is zero and determine the position of the object when this occurs.
a) i cant seem to get the derivative of this correct.
b) v(t)=0 solve for t. how do i figure out the position?